JAVA认证真题:SCJP考试真题及解析
来源:优易学  2011-11-28 10:45:22   【优易学:中国教育考试门户网】   资料下载   IT书店

 

  例题7:

  True or False: Readers have methods that can read and return floats and doubles.

  A. Ture

  B. False

  解答:B

  点评: Reader/Writer只处理Unicode字符的输入输出。float和double可以通过stream进行I/O.

  例题8:

  What does the following paint() method draw?

  1. public void paint(Graphics g) {

  2. g.drawString(“Any question”, 10, 0);

  3. }

  A. The string “Any question?”, with its top-left corner at 10,0

  B. A little squiggle coming down from the top of the component.

  解答:B

  点评:drawString(String str, int x, int y)方法是使用当前的颜色和字符,将str的内容显示出来,并且最左的字符的基线从(x,y)开始。在本题中,y=0,所以基线位于最顶端。我们只能看到下行字母的一部分,即字母‘y’、‘q’的下半部分。

  例题9:

  What happens when you try to compile and run the following application? Choose all correct options.

  1. public class Z {

  2. public static void main(String[] args) {

  3. new Z();

  4. }

  5.

  6. Z() {

  7. Z alias1 = this;

  8. Z alias2 = this;

  9. synchronized(alias1) {

  10. try {

  11. alias2.wait();

  12. System.out.println(“DONE WAITING”);

  13. }

  14. catch (InterruptedException e) {

  15. System.out.println(“INTERR
  UPTED”);

  16. }

  17. catch (Exception e) {
 
  18. System.out.println(“OTHER EXCEPTION”);

  19. }

  20. finally {

  21. System.out.println
  (“FINALLY”);

  22. }

  23. }

  24. System.out.println(“ALL DONE”);

  25. }

  26. }

  A. The application compiles but doesn't print anything.

  B. The application compiles and print “DONE WAITING”

  C. The application compiles and print “FINALLY”

  D. The application compiles and print “ALL DONE”

  E. The application compiles and print “INTERRUPTED”

  解答:A

  点评:在Java中,每一个对象都有锁。任何时候,该锁都至多由一个线程控制。由于alias1与alias2指向同一对象Z,在执行第11行前,线程拥有对象Z的锁。在执行完第11行以后,该线程释放了对象Z的锁,进入等待池。但此后没有线程调用对象Z的notify()和notifyAll()方法,所以该进程一直处于等待状态,没有输出。

  例题10:

  Which statement or statements are true about the code listed below? Choose three.

  1. public class MyTextArea extends TextArea {

  2. public MyTextArea(int nrows, int ncols) {

  3. enableEvents(AWTEvent.TEXT_
  EVENT_MASK);

  4. }

  5.

  6. public void processTextEvent
  (TextEvent te) {

  7. System.out.println(“Processing a text event.”);

  8. }

  9. }

  A. The source code must appear in a file called MyTextArea.java

  B. Between lines 2 and 3, a call should be made to super(nrows, ncols) so that the new component will have the correct size.

  C. At line 6, the return type of processTextEvent() should be declared boolean, not void.

  D. Between lines 7 and 8, the following code should appear: return true.

  E. Between lines 7 and 8, the following code should appear: super.processTextEvent(te).

  解答:A, B, E

  点评:由于类是public,所以文件名必须与之对应,选项A正确。如果不在2、3行之间加上super(nrows,ncols)的话,则会调用无参数构建器TextArea(), 使nrows、ncols信息丢失,故选项B正确。在Java2中,所有的事件处理方法都不返回值,选项C、D错误。选项E正确,因为如果不加super.processTextEvent(te),注册的listener将不会被唤醒。

  1.Which statement about the garbage collection mechanism are true?
A. Garbage collection require additional programe code in cases where multiple threads are running.
B. The programmer can indicate that a reference through a local variable is no longer of interest.

C. The programmer has a mechanism that explicity and immediately frees the memory used by Java objects.
D. The garbage collection mechanism can free the memory used by Java Object at explection time.
E. The garbage collection system never reclaims memory from objects while are still accessible to running user threads.

  1。B、E
JAVA的垃圾回收机制是通过一个后台系统级线程对内存分配情况进行跟踪实现的,对程序员来说是透明的,程序员没有任何方式使无用内存显示的、立即的被释放。而且它是在程序运行期间发生的。
答案B告诉我们程序员可以使一个本地变量失去任何意义,例如给本地变量赋值为“null”;答案E告诉我们在程序运行期间不可能完全释放内存。


2. Give the following method:
1) public void method( ){
2) String a,b;
3) a=new String(“hello world”);
4) b=new String(“game over”);
5) System.out.println(a+b+”ok”);
6) a=null;
7) a=b;
8) System.out.println(a);
9) }
In the absence of compiler optimization, which is the earliest point the object a refered is definitely elibile to be garbage collection.
A. before line 3
B.before line 5
C. before line 6
D.before line 7
E. Before line 9

  2。D
第6行将null赋值给a以后,a以前保存的引用所指向的内存空间就失去了作用,它可能被释放。所以对象a可能最早被垃圾回收是在第7行以前,故选择D选项。

3. In the class java.awt.AWTEvent,which is the parent class upon which jdk1.1 awt events are based there is a method called getID which phrase accurately describes the return value of this method?
A. It is a reference to the object directly affected by the cause of the event.
B. It is an indication of the nature of the cause of the event.
C. It is an indication of the position of the mouse when it caused the event.
D. In the case of a mouse click, it is an indication of the text under the mouse at the time of the event.
E. It tells the state of certain keys on the keybord at the time of the event.
F. It is an indication of the time at which the event occurred.

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