开始定义的结构体如:
typedef struct student
{
int id;
char name[20];
char sex[20];
char birthday[50];
int score;
char description[100];
void* pWnd;
}STUDENT,*PSTUDENT;
定义一个deque来保存这个结构体的对象 deque<STUDENT>m_vecst;青年人网提示有一个结构体对象，想查找是否在这个deque中，青年人网提示开始是这样做的:
STUDENT TT;
deque<STUDENT>::iterator iter = find(m_vecst.begin(),m_vecst.end(),TT);
if( iter != m_vecst.end())
{
STUDENT DD = (STUDENT)(*iter);
char* name = DD.name;
}
但是程序编译不过去，报的错误为:
**********\include\algorithm(43) : error C2678: binary '==' : no operator defined which takes a left-hand operand of type 'struct student' (or there is no acceptable conversion)
**********.cpp(549) : see reference to function template instantiation 'class std::deque<struct student,class std::allocator<struct student> >::iter
ator __cdecl std::find(class std::deque<struct student,class std::allocator<struct student> >::iterator,class std::deque<struct student,class std::allocator<struct student> >::iterator,const struct student &)' being compiled
Error executing cl.exe.
之所有这个错误，主要是我们没有定义在查找结构体STUDENT时，不知道怎么样判断结构体是相等的.因此我们必须重载结构体的==符号。.如下:
typedef struct student
{
int id;
char name[20];
char sex[20];
char birthday[50];
int score;
char description[100];
void* pWnd;
bool operator == (const student &A) const
{
if (id == A.id) return true;
return false;
}
}STUDENT,*PSTUDENT;
责任编辑：小草
