题目：
对java.util.map进行删除其中一键值对操作。
答：
/**
*
*/
package map;
import java.util.Collection;
import java.util.HashMap;
import java.util.Iterator;
import java.util.Set;
/**
* Delete key-value of an HashMap
*/
public class HashMapTest {
/**
* @param args
* @throws InterruptedException
*/
public static void main(String[] args) {
//construct an map
HashMap<Integer, String> map=new HashMap<Integer, String>();
map.put(11, "aa");
map.put(22, "bb");
map.put(33, "cc");
map.put(44, "dd");
//out print map
outPrintMap(map);
//define the value will be deleted
String deleteValue="cc";
//get which key
if (map.containsValue(deleteValue)) {
Integer key=null;
for(Iterator<Integer> keys = map.keySet().iterator();keys.hasNext();) {
Integer index=keys.next();
if (map.get(index).equals(deleteValue)) {
key=index;
System.out.println("You want to delete value:"+deleteValue+", which key is:"+key);
}
}
//remove
if (key!=null) {
map.remove(key);
}
}else{
System.out.println("Your delete value"+deleteValue+" is not exist in this map!");
}
//out print map
outPrintMap(map);
}
/**
* Out print an map
* @param map
*/
public static void outPrintMap(HashMap<Integer, String> map){
/**
* keySet
*/
Set<Integer> set=map.keySet();
Iterator<Integer> it=set.iterator();
while(it.hasNext()){
System.out.println(it.next());
}
/**
* values
*/
Collection<String> col=map.values();
Iterator<String> it1=col.iterator();
while(it1.hasNext()){
System.out.println(it1.next());
}
}
}
责任编辑：小草
